hinpunan penyelesaian [tex] \frac{1}{2} x+ \frac{1}{5} y=2 \frac{2}{5} dan \frac{1}{3} x- \frac{2}{5} y= \frac{8}{15} [/tex]

[tex]\frac{2}{2}x+\frac{2}{5}y=\frac{24}{5}$ (Kalikan 2, jadi gitu)$ \\ \frac{1}{3}x-\frac{2}{5}y=\frac{8}{15} \\ --$Jumlahkan$-- \\ \frac{4}{3}x=\frac{80}{15} \\ x=\frac{16}{3}\times\frac{3}{4}=4 \\ \\ \frac{1}{3}x-\frac{2}{5}y=\frac{8}{15} \\ \frac{4}{3}-\frac{2}{5}y=\frac{8}{15} \\ \frac{2}{5}y=\frac{4}{3}-\frac{8}{15} \\ \frac{2}{5}y=\frac{12}{15} \\y=\frac{12}{15}\times\frac{5}{2}=2 \\ HP=\{(x,y)|(4,2)\}[/tex]