Matematika

Pertanyaan

bentuk sedeehana daru (2/7+6/5)(3/7-4/5)

2 Jawaban

  • (2/7 + 6/5)(3/7 - 4/5)
    = (10+42)/35 x (15-28)/35
    = 52/35 x (-17)/35
    = -884/1.225
  • (2/7+6/5)(3/7-4/5)
    = 2/7×3/7+2/7×(-4/5)+6/5×3/7+6/5×(-4/5)
    = 6/49+(-8/35)+18/35+(-24/25)
    = 150/1225-280/1225+630/1225-1176/1225
    = -676/1225

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