persamaan garis yang melalui titik (2,1) dan (3,6) adalah?*gunakan car

[tex]\displaystyle \frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1} \\ \\ \frac{y-1}{6-1}=\frac{x-2}{3-2} \\ \\ \frac{y-1}{5}=\frac{x-2}{1} \\ 1(y-1)=5(x-2) \\ y-1=5x-10 \\ y=5x-9[/tex]

y -y₁    =    x -x₁
y₂ -y₁        x₂ -x₁

y -1    =    x -2
6 -1          3 -2

y -1    =  x -2
5            1

1(y -1) = 5(x -2)
y -1 = 5x -10
y = 5x -10 +1
y = 5x -9
atau
-5x +y +9 = 0