tolong kerjakan pakai cara kerja.

[tex] x^{2} - 4x + 3\\=(x-3)(x-1)[/tex]
x1 = 3       dan     x2 = 1

[tex] x_{1}^{2} = 3^{2} = 9[/tex]
[tex] x_{2}^{2} = 1^{2} = 1[/tex]

(x-[tex] x_{1}^{2} [/tex])(x-[tex] x_{2}^{2} [/tex])
= (x-9)(x-1)
= [tex] x^{2} - 9x - x + 9\\= x^{2} -10x +9[/tex]