Pers. garis m yg melalui titik (4,-3) adalah

ax + by + c = 0
m = -a/b
4y - 6x + 10 = 0
a = -6
b = 4
c = 10
m = -(-6)/4 = 3/2
Tegak lurus, maka m1.m2 = -1
3/2.m2 = -1
m2 = -2/3 melalui titik (4, -3)
(y - y1) = m(x - x1)
(y - (-3)) = -2/3(x - 4)
(y + 3) = -2/3(x - 4)
3(y + 3) = -2(x - 4)
3y + 9 = -2x + 8
3y = -2x + 8 - 9
3y = -2x - 1
2x + 3y = -1