X^2+3x-40 ÷ x^2-25 dapat disederhanakan menjadi?

Kelas 8 Matematika
Bab Bentuk Aljabar

(x² + 3x - 40)/(x² - 25)
= ((x + 8) (x - 5)) / ((x + 5) (x - 5))
= (x + 8)/(x + 5)

≡ penyelesaian :

[tex] = \frac{ {x}^{2} + 3x - 40 }{ {x}^{2} - 25 } \\ \\ = \frac{ {x}^{2} + 8x - 5x - 40 }{(x - 5)(x + 5)} \\ \\ = \frac{x(x + 8) - 5(x + 8)}{(x - 5) (x + 5)} \\ \\ = \frac{(x - 5)(x + 8)}{(x - 5)(x + 5)} \\ \\ = \frac{x + 8}{x + 5} [/tex]