berapa pH asam sulfat 0,1M

(H) = a x Ma
= 2 x 0,1
=0,2
=2 x 10pangk-1


pH = -log 2x 10 pangk-1
= 1 -log 2

Mapel: Kimia
Kelas: X
Materi: Asam Basa

Jawab

H2SO4→ 2H+ + SO4²-

[H+] = x × Ma
[H+] = 2×0.1
[H+] = 0.2
[H+] = 2×10-¹

pH= -log[H+]
pH= -log 2×10-¹
pH= 1-log 2
pH= 1-0.3
pH= 0.7