7 per 8 dikali 41 per 2 dikurang 3 per 4 + 2 per 3 =
Matematika
sinta6661
Pertanyaan
7 per 8 dikali 41 per 2 dikurang 3 per 4 + 2 per 3 =
2 Jawaban
-
1. Jawaban hafiyyah
(7/8) x (41/2) - (3/4) + (2/3)
(287/16) - (3/4) + (2/3)
= 857/48
= 17 41/48
= 17,854 -
2. Jawaban Basskeen
7/8 × 41/2 = 287/16 - 3/4 = 287/16 - 12/16 = 275/16 + 2/3 = 735/48 + 32/48 = 703/48 = 14 31/48