Fisika

Pertanyaan

tolong dijawab ya pake cara
tolong dijawab ya pake cara

1 Jawaban

  • Qa-b= m×c×*segitiga t massa diubah dulu 500 gram= (5×10^-1)
    =(5×10^-1)×2100×(-10-0)
    =5×210×10
    = 10500 joule
    Qb-c= m×lebur es
    =(5×10^-1)×(336000)
    = 5×33600
    = 168000 joule
    Jadi, Q.total= Qa-b+Qb-c
    = 10500+168000
    =178500 joule di ubah 178500:1000= 178,5 kJ/kilo Joule
    Maaf kalo salah