Tolong jawab dengan cara ya.

Kelas 8 Matematika
Bab Persamaan Garis

(4,0) dan (0,6)

m1 = (y2 - y1)/(x2 - x1)
m1 = (6 - 0)/(0 - 4)
m1 = -6/4
m1 = -3/2

Tegak lurus
m1 . m2 = -1
-3/2 . m2 = -1
m2 = -1 . -2/3
m2 = 2/3

(-2, 0)

y - y1 = m (x - x1)
y - 0 = (2/3) . (x + 2)
3y = 2x + 4
2x - 3y + 4 = 0