lingakaran memiliki luas 1.256cm2 diameter

Kelas 5 Matematika
Bab Pengukuran

Luas = 1.256
1/4 x π x d x d = 1.256
1/4 x 3,14 x d² = 1.256
d² = 1.256 x 4/3,14
d = √(1.600)
d = 40 cm

[tex]l \: = \pi {r}^{2} \\ 1256 \: {cm}^{2} = 3.14 {r}^{2} \\ {r}^{2} = 1256 \div 3.14 \\ {r}^{2} = 400 \\ r \: = \sqrt{400} \\ r \: = 20 \: cm \\ \\ d \: = r \: \times 2 \\ = 20 \times 2 \\ = 40 \: cm[/tex]