kemiringan tangga tsb adalah?
Matematika
yogaku
Pertanyaan
kemiringan tangga tsb adalah?
1 Jawaban
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1. Jawaban dharmawan14
AC^2 = AB^2 + BC^2..(Phitagoras )
AB^2 = AC^2 - BC^2
AB^2 = 15^2 - 12^2
AB^2 = 225 - 144
AB^2 = 81
AB = V81
AB = 9
kemiringan = BC/AB
= 12/9
= 4/3