tolong gi mana caranyaa kerjanya

Let's me answer your question :)
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■ Mapel Math
■ Materi Teorema Pythagoras

Jawaban :
Panjang BD
[tex] = \sqrt{ {8}^{2} + {6}^{2} } \\ = \sqrt{64 + 36} \\ = \sqrt{100} [/tex]
= 10 cm

Panjang BC
[tex] = \sqrt{ {26}^{2} - {10}^{2} } \\ = \sqrt{676 - 100} \\ = \sqrt{576} [/tex]
= 24 cm

The best for you friends :)
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Semoga Membantu

[tex] db \: = {8}^{2} + {6}^{2} = 64 + 36 = \sqrt{100 = 10} [/tex]
[tex] {26}^{2} = {10}^{2} + bc \\ 676 = 100 + {bc}^{2} \\ bc = \sqrt{576 } \\ bc \: = 24[/tex]