perhatikan gambar berikut diketahui besar <BOC = (x+3)° dan <COD = (4x+2)°. besar <AOB adalah...

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  • <AOD = 90°

    <COD = 4x + 2 = 90°
    4x = 88
    x = 22

    <COB = x + 3 = 22 + 3 = 25°

    <AOB = 180° - 25° = 155°

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