Hasil dari |(4x3-9x2+2x+5)dx=

[tex] = 4 \times \frac{ {x}^{3 + 1} }{3 + 1} - 9 \times \frac{ {x}^{2 + 1} }{2 + 1} + 2 \times \frac{ {x}^{1 + 1} }{1 + 1} + 5x + c \\ = 4 \times \frac{ {x}^{4} }{4} - 9 \times \frac{ {x}^{3} }{3} + 2 \times \frac{ {x}^{2} }{2} + 5x + c \\ = {x}^{4} - {3x}^{3} + {x}^{2} + 5x + c[/tex]