x² + 3x - 10= 0 adalah p dan q. jika p > q, nilai p² - q adalah...

[tex] x^{2} [/tex] + 3x - 10 = 0
(x +5)(x-2) = 0
x = -5 atau x = 2
p>q
p=2
q=-5
[tex] p^{2} [/tex]-q = ?
[tex] 2^{2} [/tex] - (-5)
4-(-5)=9

x^2 + 3x - 10 = 0
(x + 5) (x - 2) = 0

x+5=0
x=-5

x-2=0
x=2

syarat : p > q
2 > -5

jadi p = 2 , q = -5

p^2-q =
2^2 - (-5) =
4 + 5 =
9