koordinat titik balik grafik fungsi y=x2-2x-15

Kelas 10 Matematika
Bab Fungsi Kuadrat

y = x² - 2x - 15
a = 1; b = -2; c = -15

Sumbu simetri
= -b/2a
= - (-2)/(2 . 1)
= 1

y = x² - 2x - 5
y = 1² - 2 . 1 - 5
y = -6

Koordinat titik balik = (1, -6)