f(×) = x-3 fog(×) = xpangkat2 - 6x - 7 tentukan g(x) = ?

Mapel : Matematika

Kelas : 10

Bab : Relasi dan Fungsi
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f(x) = x - 3

(f o g) (x) = x² - 6x - 7

Ditanya → Nilai fungsi g(x)

Jawaban :

(f o g) (x) = x² - 6x - 7

f(g(x)) = x² - 6x - 7

g(x) - 3 = x² - 6x - 7

g(x) = x² - 6x - 7 + 3

g(x) = x² - 6x - 4 ✔