tentukan lim x-> ~ dari √x^2+4X-2 - (x+3) mohon bantuannya yaa

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[tex] \lim_{x \to \infty} \sqrt{ x^{2} + 4x - 2} - (x + 3)
= \lim_{x \to \infty} \sqrt{ x^{2} + 4x - 2} - \sqrt{ (x+3)^{2} }[/tex]
= \lim_{x \to \infty} \sqrt{ x^{2} + 4x - 2} - \sqrt{[tex] x^{2} + 6x + 9[/tex] }[/tex]

rumus = 
[tex] \lim_{x \to \infty} \sqrt{a x^{2} + bx + c} - \sqrt{a x^{2} + px + q} [/tex] = [tex] \frac{b - p}{2 \sqrt{a} } [/tex]

sehingga menjadi [tex] \frac{b-p}{2 \sqrt{a} } = \frac{4-6}{2 \sqrt{1} } = \frac{-2}{2} = -1[/tex]

semoga bermanfaat