9log 243 dengan basis 3 Please bantu ya gays

[tex]^{9} log243 = ^{3 ^{2} } log3 ^{5} \\ = \frac{5}{2} . ^{3} log3 = \frac{5}{2} [/tex]

9log 243 = log 243/ log 9
= log 3^5 / log 3^2
= 5.log 3 / 2.log 3
= 5/2