perbandingan luas permukaan dua buah balok yg berukuran (6×4×2)cm dan (8×6×4)cm adalah???(cara nya) A. 2:3 B. 3:4 C. 11:26 D. 11:28

Lp Balok 1
= 2 × [ (6 × 4) + (6 × 2) + (4 × 2) ]
= 2 × (24 + 12 + 8)
= 2 × 44
= 88 cm²

Lp Balok 2
= 2 × [ (8 × 6) + (8 × 4) + (6 × 4) ]
= 2 × (48 + 32 + 24)
= 2 × 104
= 208 cm²

● Perbandingan ●
= 88 : 208 (Masing² dibagi 8)
= 11 : 26

Jawaban: C

Luas Balok 1
= 2 (pl+pt+lt)
= 2 ((6x4)+(6x2)+(4x2))
= 2 ((24)+(12)+(8))
= 2 (44)
= 88 cm²

Luas balok 2
= 2 (pl+pt+lt)
= 2 ((8x6)+(8x4)+(6x4))
= 2 ((48)+(32)+(24))
= 2 (104)
= 208 cm²

Maka perbandingannya
= 88 : 208
= 11 : 26

Jawabannya adalah C