tolong nomr 2 & 3 yaaa
Matematika
nesya1112
Pertanyaan
tolong nomr 2 & 3 yaaa
1 Jawaban
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1. Jawaban emilyapg
3.) x̅gab = x̅1n1 + x̅2n2 / n1 + n2
52,75 = 51(25) + x̅2(35) / 25 + 35
52,75 = 1275 + 35x̅2 / 60
3165 = 1275 + 35x̅2
3165 - 1275 = 35x̅2
1890 = 35x̅2
54 = x̅2