Matematika

Pertanyaan

8log 7 =p, maka 16 log 28=

1 Jawaban

  • 8log7 = p
    ²^³log 7 = p
    16log28 = 8log28/8log16
    = (8log4 + 8log7)/(8log8 + 8log2)
    = ( ⅔ + p)/( 1 + ⅓)
    = (⅔ + p) / (4/3)
    = ¾(⅔ + p )
    = ½ + ¾p
    = ¼(2 + 3p)

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